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• You're talking about Java and not Javascript? (Score:2)

  by merlyn (47)

  According to the first hit I got for "java block local variables" [sun.com], it looks like the variable declared in your "for" statement is actually outside the scope of that local block, but otherwise, the scope of a local variable inside a block is in fact inside the block and may temporarily obscure outer variables.

  Now in JavaScript, the rules are different, but I presume you're smart enough not to say "Java" when you mean "JavaScript".

  --
  

  • Randal L. Schwartz
  • Stonehenge
  • Re:You're talking about Java and not Javascript? (Score:2)

    by Mr. Muskrat (4572) <reversethis-{moc ... ta} {tarksum.rm}> on 2008.09.27 10:21 (#65153) Journal

    Considering he does Java programming most of the time now, I doubt he'd mistakenly call JavaScript Java.

    I haven't written any Java since about 1998 and I try not to read it too often as it usually makes my head hurt. ;)

    But if I'm reading this right, it looks like the for loop would need to be enclosed inside another block for it to work like J. David is expecting...

    void methodName() {
      int i = 7;
      {
        for (int j = 0; j < 10; j++) {
          int i = j * 2;
        }
      }
    }

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