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How about using $+ ? (Score:2)
TIMTOWTDI, but you don't have to jump through all those hoops, just to get one definite capture variable for every case. Just take a look at
$+[perl.org] and you'll see it was especially designed for these cases, where you have captures in alternatives and you don't know which alternative matched. So, you can just use your 2 captures regex, and simply get the one you want with$+.But, I think this probably is not such a good idea. You ought to strip the backslashes in those quoted strings that are just there to esc
Re: (Score:1)
Two upsides of using conditional match:
The boolean flag makes it particularly nice to make the backslash stripping conditional on the presence of quotes.