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List nit (Score:1)

by runrig (3385)

"list" is already a function name, so I wouldn't use it as a variable. This wouldn't happen if the language had sigils...
- Re: (Score:1)
  
  by jrockway (7171)
  
  This isn't a problem. Symbols get their values from different "slots" depending on context. When you write (list 'foo 'bar), list is called as a function. When you write (setq list 42) and then (+ list list), you get 84. It's very clear. The only problem is calling a function saved in the value slot of a symbol: (defun foo (a b) (- a b)) (let ((foo (lambda (a b) (+ a b)))) (foo 2 1) ; 1 (funcall foo 2 1)) ; 3 Oh well, you can't have everything.
  - Re:List nit (Score:1)
    
    by jrockway (7171) on 2008.01.31 17:09 (#60781) Journal
    
    Ugh, apologies for the worthless formatting.
    
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