use Perl

How is this possible? Well, %cpu is calculated with "time(NULL) - start"* as the denominator. However, if the program takes <= 1 second to run, then time(NULL) - start ends up being 0, since Linux doesn't store fractional seconds in /proc.

I have a few potential solutions:
1) I could ignore the calling program as a process. This is cheating, and command line 'top' does report itself. How accurate it is on the first read is another story.
2) I could cheat and simply set the %cpu to 100 (or 0) in the event of a NaN.
3) I could let the programmer worry about the possibility of a NaN.
4) I could cheat even worse by throwing a "sleep 1" in the extension so that I'm always guaranteed to avoid a NaN. But, that could taint the other results.

Suggestions?

* Full formula for calculating %cpu on Linux:

start = btime + starttime/CLK_TCK;
pcpu = ( ((float)utime + (float)stime) / CLK_TCK ) / (time(NULL) - start);
pcpu *= 100;